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18.1.3 Solve problems involving [H+(aq)], [OH-(aq)], pH and pOH IB Chemistry HL

pH = -log [H+] [H+] = 10^-pHpOH = -log [OH-] [OH-] = 10^-pOHThis looks nasty but it's not as bad as it looks. Most people seem to have trouble using their calculator on these though.
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