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Word Problem: Algebra with Coins

Check out Bas Rutten's Liver Shot on MMA Surge: http://bit.ly/MMASurgeEp1 In this video, Mahalo's math expert Allison Moffett offers a word problem that requires some knowledge of Algebra to solve. Word Problem: Algebra with Coins --------------------------------------------------------------------- The following is a word problem that requires some knowledge of Algebra to solve. A wallet contains the same number of pennies, nickels and dimes totaling $1.44. How many of each type of coin does the wallet contain? 1. 6 of each 2. 9 of each 3. 12 of each 4. 15 of each 5. 16 of each Solution --------------------------------------------------------------------- To solve this problem, the first thing you need to do is set up your algebraic equation. You know that you have the same number of pennies, nickels and dimes, so you can call that number X. The sum of these coins together makes $1.44. Take the number of pennies (X) and multiply it by how much a penny is worth (0.01). Add the number of nickels (X) and multiply that number by how much a nickel is worth (0.05), and finally add the number of dimes (X) multiplied by their worth (0.10). The equation should look like this: * X(0.01) + X(0.05) + X(0.10) = 1.44 You can combine the parentheses so the equation becomes this: * X(0.01 + 0.05 + 0.10) = 1.44 Add the numbers in the parentheses together and rewrite the equation: * X(0.16) = 1.44 To solve for X, divide 1.44 by 0.16. The answer is 9. Read more by visiting our page at: http://www.mahalo.com/word-problem-algebra-with-coins/
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